x/(x-3)=9/(x^2-3x)

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Solution for x/(x-3)=9/(x^2-3x) equation:


D( x )

x^2-(3*x) = 0

x-3 = 0

x^2-(3*x) = 0

x^2-(3*x) = 0

x^2-3*x = 0

x^2-3*x = 0

DELTA = (-3)^2-(0*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+3)/(1*2) or x = (3-9^(1/2))/(1*2)

x = 3 or x = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x in (-oo:0) U (0:3) U (3:+oo)

x/(x-3) = 9/(x^2-(3*x)) // - 9/(x^2-(3*x))

x/(x-3)-(9/(x^2-(3*x))) = 0

x/(x-3)-9*(x^2-3*x)^-1 = 0

x/(x-3)-9/(x^2-3*x) = 0

x^2-3*x = 0

x^2-3*x = 0

x*(x-3) = 0

x-3 = 0 // + 3

x = 3

x*(x-3) = 0

x/(x-3)-9/(x*(x-3)) = 0

(x^2)/(x*(x-3))-9/(x*(x-3)) = 0

x^2-9 = 0

(x^2-9)/(x*(x-3)) = 0

(x^2-9)/(x*(x-3)) = 0 // * x*(x-3)

x^2-9 = 0

1*x^2 = 9 // : 1

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x in { 3}

x = -3

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